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What's mean ORA-25191?
modb.pro

在参考了Using DBMS_SYS_SQL Package to grant Privilege留言板里有朋友继续问道,出现了以下错误:
ORA-25191: cannot reference overflow table of an index-organized table 
ORA-06512: at "SYS.DBMS_SYS_SQL", line 1474 
ORA-06512: at line 9 

查一下Oracle手册,我们看到:
ORA-25191 cannot reference overflow table of an index-organized table

Cause: An attempt was made to directly access the overflow table of an index-organized table.
Action: Issue the statement against the parent index-organized table containing the specified overflow table.


意思是说,对于Overflow的IOT表,只需要对父表进行授权即可。简单动手自己试试看也可以:
SQL> connect eygle/eygle
Connected.
SQL> CREATE TABLE TEST_IOT
  2        (id NUMBER PRIMARY KEY,
  3         C1 VARCHAR2(50),
  4         C2 VARCHAR2(10))
  5        ORGANIZATION INDEX PCTTHRESHOLD  10 OVERFLOW;

Table created.

SQL> col object_name for a30
SQL> select object_name,object_type from user_objects where object_name like '%IOT%';

OBJECT_NAME                    OBJECT_TYPE
------------------------------ ------------------
SYS_IOT_OVER_7370              TABLE
SYS_IOT_TOP_7370               INDEX
TEST_IOT                       TABLE

SQL> grant select on SYS_IOT_OVER_7370 to scott;
grant select on SYS_IOT_OVER_7370 to scott
                *
ERROR at line 1:
ORA-25191: cannot reference overflow table of an index-organized table

SQL> 

Ok,那么接下来的就简单了,只要把我们之前的过程简单修改一下:
declare 
sqltext varchar2(200); 
c integer; 
begin 
for userlist in (select user_id,username from all_users where username not in ('SYS','SYSTEM','EYGLE')) loop 
for tablelist in (select owner,table_name from dba_tables where owner = userlist.username and table_name not like '%IOT_OVER%') loop 
sqltext := 'grant all on '||tablelist.owner||'.'||tablelist.table_name ||' to eygle with grant option'; 
c := sys.dbms_sys_sql.open_cursor(); 
sys.dbms_sys_sql.parse_as_user( c,sqltext,dbms_sql.native,userlist.user_id); 
sys.dbms_sys_sql.close_cursor(c); 
end loop; 
end loop; 
end; 
/ 

这样就可以了.

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By eygle on 2005-05-09 20:24 | Comments (0) | SQL.PLSQL | 280 |


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